A) \[\Delta H=\Delta E-RT\]
B) \[\Delta H=\Delta E+RT\]
C) \[\Delta H=\Delta E+2RT~\]
D) \[\Delta H=\Delta E-2RT~\]
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}OH(l)+3{{O}_{2}}(g)\xrightarrow{{}}2C{{O}_{2}}(g)+3{{H}_{2}}O(l)\] \[\Delta {{n}_{g}}=2-3\] \[\therefore \] \[\Delta {{n}_{g}}=-1\] On applying, \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] \[\therefore \] \[\Delta H=\Delta E-RT\]You need to login to perform this action.
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