A) \[2.14V\]
B) \[4.28V\]
C) 6.42V
D) \[8.56V\]
Correct Answer: A
Solution :
\[\Delta G=-827\,kJ\,mo{{l}^{-1}}\] We know that \[\Delta G=-nEF\{n=4\}\] \[\therefore \] \[-827\times {{10}^{3}}J=-4\times E\times 96500\] \[\therefore \] \[E=\frac{827\times {{10}^{3}}}{4\times 96500}\] \[\therefore \] \[E=2.14V\]You need to login to perform this action.
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