A) \[{{L}_{2}},{{L}_{3}}\]
B) \[{{L}_{1}},{{L}_{4}}\]
C) \[{{L}_{1}},{{L}_{2}}\]
D) \[{{L}_{4}},{{L}_{1}}\]
Correct Answer: D
Solution :
Length of tube \[=10cm\] \[{{f}_{o}}+{{f}_{e}}=10cm\] Magnification \[m=\frac{{{f}_{o}}}{{{f}_{e}}}=4\] \[{{f}_{o}}=4{{f}_{e}}\] Putting in Eq. (i), \[5{{f}_{e}}=10cm\] or \[{{f}_{e}}=2cm\] and \[{{f}_{o}}=8cm\] \[{{f}_{o}}=8cm,\] \[{{f}_{e}}=2cm\] Hence, \[{{L}_{4}}\] and \[{{L}_{1}}\] will be used.You need to login to perform this action.
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