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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    A block B is pushed momentarily along a horizontal surface with an initial velocity v. If µ is the coefficient of sliding friction between B and the surface, block B will come to rest after a time

    A) \[\frac{v}{g\mu }\]                                         

    B) \[\frac{g\mu }{v}\]

    C) \[\frac{g}{v}\]                                   

    D) \[\frac{v}{g}\]

    Correct Answer: A

    Solution :

    Block B will come to rest, if force applied to it will vanish due to frictional force acting between block B and surface, ie, \[force\text{ }applied=\text{ }frictional\text{ }force\] ie,           \[\mu mg=ma\] or            \[\mu mg=m\left( \frac{v}{t} \right)\]                 or            \[t=\frac{v}{\mu g}\]


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