A) \[0.02\]
B) \[0.05\]
C) \[0.04\]
D) \[0.07\]
Correct Answer: B
Solution :
Change in oxidation number \[=(+7)-(+2)=5\] \[\therefore \] Normality of solution \[=5\times 0.04=0.20\text{ }N\] Volume \[=250mL\] \[\therefore \] Number of equivalents of \[KMn{{O}_{4}}\] \[=0.20\times \frac{250}{1000}=0.05\]You need to login to perform this action.
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