A) 20\[\Omega \]
B) 2\[\Omega \]
C) 0.2\[\Omega \]
D) 2\[\Omega \]
Correct Answer: B
Solution :
Key Idea The potential difference across ammeter and shunt is same. Let \[{{i}_{a}}\] is the current flowing through ammeter and i is the total current. So, a current \[-{{i}_{a}}\] in will flow through shunt resistance. Potential difference across ammeter and shunt resistance is same. ie, \[{{i}_{a}}\times R=(i-{{i}_{a}})\times S\] or \[S=\frac{{{i}_{a}}R}{i-{{i}_{a}}}\] ...(i) Given, \[{{i}_{a}}=100A,\] \[i=750A,\] \[R=13\Omega \] Hence, \[S=\frac{100\times 13}{750-100}=2\Omega \]You need to login to perform this action.
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