A) T
B) 3T
C) 9T
D) \[3\sqrt{3}T\]
Correct Answer: D
Solution :
According to Kepler's law of planetary motion \[\frac{{{T}_{1}}}{{{T}_{2}}}={{\left( \frac{{{R}_{1}}}{{{R}_{2}}} \right)}^{3/2}}={{\left( \frac{R}{3R} \right)}^{3/2}}\] \[\Rightarrow \] \[{{T}_{2}}=3\sqrt{3}{{T}_{1}}\]You need to login to perform this action.
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