A) 4.43 m/s
B) 2 m/s
C) 0.5 m/s
D) 19.6 m/s
Correct Answer: A
Solution :
By applying law of conservation of energy \[mgR=\frac{1}{2}m{{v}^{2}}\] \[\Rightarrow \] \[v=\sqrt{2Rg}\] \[=\sqrt{2\times 1\times 10}\] \[=4.43m/s\]You need to login to perform this action.
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