question_answer

Acetone undergoes reduction with hydrazine in the presence of \[NaOH\]to form propane. This reaction is known as

A)  Clemmensen reduction

B)  Wolff-Kishner reduction

C)  Rosenmund reduction

D)  Reformat sky reaction

Correct Answer: B

Solution :

Reduction of ,  group to  group in the presence of \[N{{H}_{2}}N{{H}_{2}}\] (hydrazine) and \[NaOH\]is called Wolff-Kishner reduction. \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}+N{{H}_{2}}.N{{H}_{2}}\xrightarrow{NaOH}\]\[C{{H}_{3}}C{{H}_{2}}C{{H}_{3}}+{{N}_{2}}+{{H}_{2}}O\]