A) \[3\]
B) \[10.5\]
C) \[11\]
D) \[7.5\]
Correct Answer: C
Solution :
\[[O{{H}^{-}}]=\sqrt{{{K}_{b}}.C}=\sqrt{1.0\times {{10}^{-5}}\times 0.1}={{10}^{-3}}\] \[pOH=-\log [O{{H}^{-}}]=-\log \,{{10}^{-3}}=3\] \[pH=14-pOH=14-3=11\]You need to login to perform this action.
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