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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    The nearer point of hypermetropic eye is 40 cm. The lens to be used for its correction should have the power

    A)  + 1.5 D                                

    B)  -1.5 D

    C)  +2.5D                                  

    D)  +0.5D

    Correct Answer: C

    Solution :

    Hypermetropia can be removed by using a convex lens Focal length of used lens \[f=+d=+40\text{ }cm\]= + (defected near point) \[\therefore \] Power of lens \[=\frac{100}{f(cm)}=\frac{100}{40}\]\[=2.5D\]


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