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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2011

  • question_answer
    The latent heat of fusion of ice at \[{{0}^{o}}C\]is \[80~\,cal/g\].   Entropy   change \[(\Delta S)\]accompanying the melting of \[1\text{ }g\]of ice at \[{{0}^{o}}C\]would be (units: \[cal/g/K\])

    A)  \[273\]                                

    B)  \[8.0\]   

    C)  \[0.0\]                                 

    D)  \[0.293\]

    Correct Answer: D

    Solution :

    \[\Delta {{S}_{mel}}=\frac{\Delta {{H}_{mel}}}{T}=\frac{80}{273}=0.293cal/g/K\]


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