A) 0.024cm
B) 2.4cm
C) 0.24cm
D) 0.2cm
Correct Answer: D
Solution :
Fringe width \[\beta =\frac{\lambda D}{d}\]where, D = distance between screen and slits, d = separation of slits \[d=\frac{\lambda D}{\beta }=\frac{6000\times {{10}^{-8}}\times 40}{0.012}=0.2cm\]You need to login to perform this action.
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