A) \[10\]
B) \[8\]
C) 6
D) \[2\]
Correct Answer: C
Solution :
Number of \[\alpha \]-particles \[=\frac{238-206}{4}=8\] Number of \[\beta \]-particles \[=2\times \] number of \[\alpha \]-particles - change in atomic number \[\therefore \] Number of \[\beta \]-particles \[=2\times 8(-92-82)=16-10=6\]You need to login to perform this action.
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