CLAT CLAT Solved Paper-2012

  • question_answer
    If \[x={{\left( \frac{3}{2} \right)}^{2}}{{\left( \frac{2}{3} \right)}^{-4}}\] , the value of \[{{x}^{-2}}\] is

    A)  \[{{\left( \frac{2}{3} \right)}^{12}}\]                     

    B)  \[{{\left( \frac{3}{2} \right)}^{12}}\]

    C)  \[{{\left( \frac{6}{5} \right)}^{-12}}\]                    

    D)  \[{{\left( \frac{5}{6} \right)}^{-12}}\]

    Correct Answer: A

    Solution :

    Ans.   \[x={{\left( \frac{3}{2} \right)}^{2}}{{\left( \frac{2}{3} \right)}^{-4}}={{\left( \frac{3}{2} \right)}^{2}}{{\left( \frac{3}{2} \right)}^{4}}={{\left( \frac{3}{2} \right)}^{6}}\] \[\Rightarrow \]       \[{{x}^{2}}={{\left( \frac{3}{2} \right)}^{12}}\Rightarrow {{x}^{-2}}={{\left( \frac{3}{2} \right)}^{-12}}={{\left( \frac{2}{3} \right)}^{12}}\]


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