A) 5 h
B) 4 h
C) 5 h 24 min
D) 3 h
Correct Answer: C
Solution :
Ans. Part filled by pipe A in 1 \[h=\frac{1}{10}\] Part filled by pipe B in 1 \[h=\frac{1}{12}\] \[\therefore \] Total part filled by pipe A and B in 3 h \[=3\left( \frac{1}{10}+\frac{1}{12} \right)=3\,\left( \frac{6+5}{60} \right)=\frac{11}{20}\] \[\therefore \] Part left \[=1-\frac{11}{20}=\frac{9}{20}\] Now, \[\frac{9}{20}\] part is filled by pipe B in \[=\frac{9}{20}\times 12=5\] h 24 min .You need to login to perform this action.
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