A) \[\frac{5}{108}\]
B) \[\frac{1}{24}\]
C) \[\frac{103}{108}\]
D) \[\frac{17}{18}\]
Correct Answer: C
Solution :
Sol. [c] |
Total number of outcomes when three dice are thrown simultaneously = 216 |
\[\therefore \]Number of unfavorable outcome = 10 |
(1, 1, 1,) (1, 1, 2) (1, 2, 1) (2, 1, 1) (1, 2, 2) (2, 2, 1) (2, 1, 2) (1, 3, 1) (3, 1, 1) (1, 1, 3) |
\[\therefore \] Number of favorable outcome |
=216-10=206 |
\[\therefore \] Probability of getting sum at least |
\[6=\,\frac{206}{216}\,=\,\frac{103}{108}\] |
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