A) 19
B) 21
C) 23
D) 25
Correct Answer: C
Solution :
Sol. |
LCM of 15, 20 and 28 is |
LCM = \[2\times 2\times 5\times 3\times 7=420\] |
Largest number of 4-digits = 9999 |
Now, \[\frac{9999}{420}\,=\,23\frac{339}{420}\] |
\[\therefore \] Remainder = 339 |
\[\therefore \] Four digit number divisible by 15, 20 and 28 |
9999 - 339 = 9660 |
So number when divided by 15, 20 and 28 leaves Remainder |
= 9660 + 2 = 9662 |
\[\therefore \] Sum of digits = 9+6 + 6+2=23 |
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