A) ` 9025
B) ` 9152
C) ` 9215
D) ` 9251
Correct Answer: B
Solution :
Sol. [b] |
When the Principal P Amounts A in n years using compound interest then |
\[A=P{{\left( 1+\frac{r}{100} \right)}^{n}}\] |
\[\therefore \,\,\,P{{\left( 1+\frac{r}{100} \right)}^{2}}\] . (i) |
and \[10684\,=\,P{{\left( 1+\frac{r}{100} \right)}^{3}}\] .. (ii) |
divide (ii) by (i), we get |
\[\frac{10648}{9680}\,=\left( 1+\frac{r}{100} \right)\] |
\[\frac{10648}{9680}\,-1=\frac{r}{100}\] |
\[\frac{10648-9680}{9680}=\frac{r}{100}\,\] |
\[\frac{968}{9680}\,=\,\frac{r}{100}\Rightarrow r=10%\] |
Now by using eq. (i) |
\[9680\,=p{{\left( 1+\frac{10}{100} \right)}^{2}}\] |
\[p=\,9680\,\times \,\frac{100}{121}=\]` 8000 |
Now P= 8000, Time= \[1\frac{2}{5}\] yr, Rate = 10% |
\[A=8000{{\left( 1+\frac{10}{100} \right)}^{1}}\,\times \left( 1+\frac{10}{100}\times \frac{2}{5} \right)\] |
\[A=8000\times \frac{110}{100}\times \frac{26}{25}=\] `9152 |
You need to login to perform this action.
You will be redirected in
3 sec