Six dice are stacked on the floor as shown in the figure below. On each dice, the sum of numbers on opposite face is 7, i.e. if 1 is written on one face, then 6 is written on the face opposite it and so on. |
What is the maximum possible sum of numbers on the 21 visible faces? |
A) 88
B) 89
C) 96
D) 147
Correct Answer: B
Solution :
Sol. [b] |
Maximum sum of number |
\[P\,\to \,20\] \[Q\,\to \,13\] |
\[R\,\to \,18\] \[S\,\to \,13\] |
\[T\,\to \,7\] \[U\,\to \,18\] |
\[\therefore \] Total sum |
= 20 + 13 + 18 + 13 + 7 + 18 = 89 |
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