A) 4 h
B) 4 h 48 min
C) 5 h
D) 5 h 20 min
Correct Answer: B
Solution :
Sol. [b] Part of tank filled by Pipe A in 1 h = \[\frac{1}{6}\] Part of tank filled by Pipe B in 1 h = \[\frac{1}{8}\] Part of tank emitted by Pipe C in 1 h = \[\frac{1}{12}\] \[\therefore \]Total part of tank filled by A, B and C pipes working together in 1 h \[=\,\frac{1}{6}+\,\frac{1}{8}\,-\,\frac{1}{12}\] \[=\,\frac{4+3-2}{24}\,=\frac{5}{24}\] \[\therefore \]Time taken to fill the tank = \[\frac{24}{5}\,h\] = 4 h 48 minYou need to login to perform this action.
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