A) 1 %
B) 2 %
C) 4 %
D) 8 %
Correct Answer: B
Solution :
\[R\propto {{u}^{2}}\] \[\Rightarrow \] \[R=k{{u}^{2}}\] \[\Rightarrow \] \[\frac{dR}{R}=2\frac{du}{u}\] \[=2\times (1%)=2%\]You need to login to perform this action.
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