A) dextrorotatory
B) laevorotatory
C) optically inactive due to racemization
D) may be dextro or laevorotatory
Correct Answer: D
Solution :
\[{{S}_{N}}2\] reactions occur with inversion of configuration. Therefore, an optically active reactant gives an optically active product whose sign of rotation cannot be predicted i.e. option is correct.You need to login to perform this action.
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