A) \[C{{H}_{3}}CH(OH){{C}_{2}}{{H}_{5}}\]
B) \[C{{H}_{3}}CO{{C}_{6}}{{H}_{5}}\]
C) \[C{{H}_{3}}CH(OH){{C}_{6}}{{H}_{5}}\]
D) \[C{{H}_{3}}-\overset{{{C}_{2}}{{H}_{5}}}{\mathop{\overset{\mathbf{|}}{\mathop{C(OH)}}\,}}\,\,-{{C}_{6}}{{H}_{5}}\]
Correct Answer: D
Solution :
\[C{{H}_{3}}COOH\xrightarrow{PC{{l}_{5}}}\underset{(A)}{\mathop{C{{H}_{3}}COCl}}\,\xrightarrow[anhy.\,AlC{{l}_{3}}]{{{C}_{6}}{{H}_{6}}}\] \[\underset{ether\downarrow {{C}_{2}}{{H}_{5}}MgBr}{\mathop{{{C}_{6}}{{H}_{5}}COC{{H}_{3}}}}\,\] \[\underset{(C)}{\mathop{{{C}_{6}}{{H}_{5}}-\underset{{{C}_{2}}{{H}_{5}}}{\overset{OH}{\mathop{\underset{\mathbf{|}}{\overset{\mathbf{|}}{\mathop{C}}}\,}}}\,-C{{H}_{3}}}}\,\xleftarrow[{}]{{}}{{C}_{6}}{{H}_{5}}-\underset{{{C}_{2}}{{H}_{5}}}{\overset{OMgBr}{\mathop{\underset{\mathbf{|}}{\overset{\mathbf{|}}{\mathop{C}}}\,}}}\,-C{{H}_{3}}\]You need to login to perform this action.
You will be redirected in
3 sec