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CMC Medical CMC-Medical Ludhiana Solved Paper-2007

  • question_answer
    Two isolated point poles of strength 30 A-m and 60 A-m are placed at a distance of 0.3 m. The force of repulsion is

    A)  \[2\times {{10}^{-3}}N\]                             

    B)  \[2\times {{10}^{-4}}N\]

    C)  \[2\times {{10}^{5}}N\]                               

    D)  \[2\times {{10}^{-5}}N\]

    Correct Answer: A

    Solution :

                                    \[F=\frac{{{\mu }_{0}}}{4\pi }\frac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]                               \[={{10}^{-7}}\times \frac{30\times 60}{{{(0.3)}^{2}}}\]                     \[=2\times {{10}^{-3}}N\]


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