2. Solved Papers
  3. CMC Medical

CMC Medical CMC-Medical Ludhiana Solved Paper-2007

  • question_answer
    A bullet of mass 50 g travelling it 500 m/s penetrates 100 cm into a wooden block. The average force exerted on the block is

    A)  \[6.25\times {{10}^{5}}N\]         

    B)  \[26.5\times {{10}^{4}}N\]

    C)  \[6.25\times {{10}^{3}}N\]         

    D)  \[2.65\times {{10}^{4}}N\]

    Correct Answer: C

    Solution :

                    From the relation \[Fs=\frac{1}{2}m{{v}^{2}}-\frac{1}{2}m{{u}^{2}}\] \[\therefore \]  \[-F(1)=\frac{1}{2}\left( \frac{50}{1000} \right)[{{(0)}^{2}}-{{(500)}^{2}}]\]                 \[-F=-\frac{25}{1000}\times 500\times 500\]                   \[F=6.25\times {{10}^{3}}N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner