A) The reaction is first order in \[C{{l}_{2}}\]
B) The reaction is second order in NO
C) The overall order of reaction is 2
D) The overall order of reaction is 3
Correct Answer: D
Solution :
\[2NO+C{{l}_{2}}\xrightarrow{{}}2NOCl\] (i) \[r=k\,{{[NO]}^{\alpha }}\,{{[C{{l}_{2}}]}^{\beta }}=k{{a}^{\alpha }}{{b}^{\beta }}\] (ii) \[8r=k{{(2a)}^{\alpha }}{{(2b)}^{\beta }}\] (iii) \[2r=k{{(a)}^{\alpha }}{{(2b)}^{\beta }}\] Dividing (ii) by (iii) \[4={{2}^{\alpha }}\]or\[\alpha =2\] Dividing (iii) by (i) \[2={{2}^{\beta }}\]or\[\beta =1\] So, overall order = 2 + 1 = 3
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