A) Oxalic acid
B) Succinic acid
C) Glutaric acid
D) Maleic acid
Correct Answer: A
Solution :
Since, three-membered rings are quite unstable, therefore, oxalic acid on heating does not form an anhydride. Instead it decomposes to give \[C{{O}_{2}}+CO+{{H}_{2}}O\] \[\underset{COOH}{\overset{COOH}{\mathop{|}}}\,\xrightarrow{\Delta }C{{O}_{2}}+\underset{CO\,\,+\,\,{{H}_{2}}O}{\mathop{\underset{\downarrow \Delta }{\mathop{[HCOOH]}}\,}}\,\]
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