A) 600
B) 200
C) 250/n
D) 500
Correct Answer: D
Solution :
From the formula \[\omega =\frac{1}{\sqrt{LC}}\] Given : \[L=8H,\]\[C=0.5\mu F=0.5\times {{10}^{-6}}F\] \[\therefore \] \[\omega =\frac{1}{\sqrt{8\times 0.5\times {{10}^{-6}}}}\] \[\Rightarrow \] \[\omega =\frac{1}{2\times {{10}^{-3}}}=500\,\text{rad/s}\]You need to login to perform this action.
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