A) 4.5\[\Omega \]
B) 12\[\Omega \]
C) 5.4\[\Omega \]
D) 20\[\Omega \]
Correct Answer: A
Solution :
7\[\Omega \], 3\[\Omega \] are in parallel and 6\[\Omega \], 4\[\Omega \] are in parallel and both combinations are in series. So, \[{{R}_{eq}}=\frac{7\times 3}{7+3}+\frac{4\times 6}{4+6}\] \[\Rightarrow \] \[=\frac{21}{10}+\frac{24}{10}\] \[\Rightarrow \] \[=2.1+2.4\] \[\Rightarrow \] \[=4.5\,\Omega \]
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