A) 1
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
For fcc, No. of atoms at comer\[=\frac{1}{8}\times 8=1\] No. of atoms at face centre\[=\frac{1}{2}\times 6=3\] Total no. of atoms\[=1+3=4\]You need to login to perform this action.
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