A) \[1\text{/}{{r}^{2}}\]
B) \[1\text{/}r\]
C) \[r\]
D) \[{{r}^{2}}\]
Correct Answer: D
Solution :
According to formula \[v=\frac{2{{r}^{2}}(\rho -\sigma )g}{9\eta }\] So, \[v\propto {{r}^{2}}\]
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