A) \[\frac{h}{{{m}_{0}}c}\]
B) \[\frac{{{m}_{0}}c}{h}\]
C) zero
D) infinite
Correct Answer: C
Solution :
\[\lambda =\frac{h}{mv}\] where, \[m=\frac{{{m}_{0}}}{\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}}\] As \[v=c,\]then \[\Rightarrow \]\[m=\frac{{{m}_{0}}}{\sqrt{1-\frac{{{c}^{2}}}{{{c}^{2}}}}}=\frac{{{m}_{0}}}{\sqrt{1-1}}=\frac{{{m}_{0}}}{0}\] \[\Rightarrow \] \[m=\infty \] Hence, \[\lambda =\frac{h}{\infty }=0\]
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