A) \[1.5\times {{10}^{6}}\]
B) \[1.78\times {{10}^{8}}\]
C) \[2.25\times {{10}^{8}}\]
D) \[2.67\times {{10}^{8}}\]
Correct Answer: C
Solution :
Since, \[\mu v=\]constant \[\Rightarrow \] \[{{\mu }_{g}}{{v}_{g}}={{\mu }_{w}}{{v}_{w}}\] \[\Rightarrow \] \[\frac{3}{2}(2\times {{10}^{8}})=\frac{4}{3}{{v}_{w}}\] \[\Rightarrow \] \[{{v}_{w}}=2.25\times {{10}^{8}}m\text{/}s\]
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