A) \[Mg\]
B) \[Mg\left( \frac{h}{s} \right)\]
C) \[Mg\left( 1-\frac{h}{s} \right)\]
D) \[Mg{{\left( 1+\frac{h}{s} \right)}^{2}}\]
Correct Answer: B
Solution :
Velocity at the time when knife edge strikes wooden floor is\[\sqrt{2gh}\]. The velocity of \[\sqrt{2gh}\] is reduced to zero in a distances. Ifp is the average retardation, then by work-energy theorem, we have \[0-\frac{1}{2}m{{v}^{2}}=-Fs\] \[\Rightarrow \] \[F=Mg\left( \frac{h}{s} \right)\]You need to login to perform this action.
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