A) 4.0 s
B) 8.0 s
C) 2.0 s
D) 0.25 s
Correct Answer: A
Solution :
The required relation can be given as \[v=n\lambda \] Given, v = 25 m/s, \[\lambda \] = 100 m \[\therefore \] \[25=n\times 100\] \[\Rightarrow \] \[n=\frac{25}{100}=\frac{1}{4}\] \[\Rightarrow \] \[n=0.25\] Then, \[T=\frac{1}{n}=\frac{1}{0.25}=4\,s\]You need to login to perform this action.
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