A) \[\frac{{{\mu }_{0}}I}{\pi r}\]
B) \[\frac{2{{\mu }_{0}}I}{\pi r}\]
C) \[\frac{{{\mu }_{0}}I}{2\pi r}\]
D) zero
Correct Answer: D
Solution :
\[{{B}_{1}}=\frac{{{\mu }_{0}}I}{2\pi \left( \frac{r}{2} \right)}\otimes \]i.e., upwards \[{{B}_{2}}=\frac{{{\mu }_{0}}I}{2\pi \left( \frac{r}{2} \right)}\odot \]i.e., downwards Hence, net magnetic field B is zero.You need to login to perform this action.
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