A) \[\overrightarrow{a}\ne \overrightarrow{b}\]
B) \[\overrightarrow{a}\cdot \overrightarrow{b}=0\]
C) \[|\overrightarrow{a}|\,\,=\,\,|\overrightarrow{b}|\]
D) \[\overrightarrow{a}\cdot \overrightarrow{b}=1\]
Correct Answer: C
Solution :
\[(\overrightarrow{a}+\overrightarrow{b})\cdot (\overrightarrow{a}-\overrightarrow{b})=0\] \[\Rightarrow \] \[{{a}^{2}}-{{b}^{2}}=0\] \[\Rightarrow \] \[|\overrightarrow{a}|\,\,=\,\,|\overrightarrow{b}|\]You need to login to perform this action.
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