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CMC Medical CMC-Medical Ludhiana Solved Paper-2008

  • question_answer
    The pressure and temperature of 4\[d{{m}^{3}}\] of carbon dioxide gas are doubled. Then, volume of carbon dioxide gas would be

    A)  2\[d{{m}^{3}}\]                               

    B)  3\[d{{m}^{3}}\]

    C)  4\[d{{m}^{3}}\]                               

    D)  8\[d{{m}^{3}}\]

    Correct Answer: C

    Solution :

                    \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{{{p}_{1}}\times 4}{{{T}_{1}}}=\frac{2{{p}_{1}}\times {{V}_{2}}}{2{{T}_{1}}}\] \[2{{V}_{2}}=8\] \[{{V}_{2}}=\,4\,d{{m}^{3}}\]


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