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CMC Medical CMC-Medical Ludhiana Solved Paper-2009

  • question_answer
    The equation of a simple harmonic wave is given by \[y=5\sin \frac{\pi }{2}\left( 100t-x \right),\]where x and y are in metre and time is in second. The period of the wave in second will be

    A)  0.04                                      

    B)  0.01

    C)  1                                            

    D)  5

    Correct Answer: A

    Solution :

                    The given equation is \[y=5\,\sin \frac{\pi }{2}(100\,t-x)\]         ?(i) Comparing Eq. (i) with standard wave equation, given by \[y=A\text{ sin}\left( \omega t-kx \right)\]           ...(ii) we have \[\omega =\frac{100\,\pi }{2}=50\,\pi \] \[\Rightarrow \]               \[\frac{2\pi }{T}=50\,\pi \] \[\Rightarrow \]               \[T=\frac{2\pi }{50\pi }=0.04\,s\]


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