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CMC Medical CMC-Medical Ludhiana Solved Paper-2009

  • question_answer
    An air bubble of radius 1 cm rises from At bottom portion through a liquid of density 1.5 g/cc at a constant speed of 0.25\[cm\,{{s}^{-1}}\]. If the density of air is neglected, the coefficient of viscosity of the liquid is approximately, (In Pa)

    A)  13000                                  

    B)  1300

    C)  130                                       

    D)  13

    Correct Answer: C

    Solution :

                    \[v=\frac{2}{9}\frac{{{r}^{2}}\rho g}{\eta }\] \[\Rightarrow \]               \[\eta =\frac{2}{9}\cdot \frac{{{r}^{2}}\rho g}{v}\]    \[=\frac{2}{9}\frac{{{(1\times {{10}^{-2}})}^{2}}\times (1.5\times {{10}^{3}})\times 9.8}{0.25\times {{10}^{-2}}}\]    \[=130\,\,Pa\text{-}s\]


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