A) 392
B) 31.6
C) 278
D) 156
Correct Answer: A
Solution :
Mohrs salt is\[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\cdot FeS{{O}_{4}}\cdot 6{{H}_{2}}O.\] The equation is: \[5F{{e}^{2+}}+MnO_{4}^{-}+8{{H}^{+}}\xrightarrow{{}}\]\[5F{{e}^{3+}}+M{{n}^{2+}}+4{{H}_{2}}O\] Total change in oxidation number of iron \[=(+3)-(+2)\] \[=+\,1\] So, equivalent wt. of Mohrs salt \[=\frac{\text{Mol}\text{. wt}\text{. of Mohr}\,\text{ }\!\!\!\!\text{ s salt}}{\text{1}}\] \[=\frac{392}{1}\] \[=392\]You need to login to perform this action.
You will be redirected in
3 sec