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CMC Medical CMC-Medical Ludhiana Solved Paper-2010

  • question_answer
    The average kinetic energy of an ideal gas per molecule in SI units at \[25{}^\circ C\] will be

    A)  \[6.17\times {{10}^{-21}}\,kJ\] 

    B)  \[6.17\times {{10}^{-21}}\,J\]

    C)  \[6.17\times {{10}^{-20}}\,J\]   

    D)  \[7.16\times {{10}^{-20}}\,J\]

    Correct Answer: B

    Solution :

                    Average kinetic energy per molecule \[=\frac{3}{2}KT\] \[=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 300\,J\] \[=6.17\times {{10}^{-21}}J\]


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