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CMC Medical CMC-Medical Ludhiana Solved Paper-2010

  • question_answer
    The molal elevation constant of water is\[0.52{}^\circ C\]. The boiling point of 1.0 molal aqueous KCl solution (assuming complete dissociation of KCl), therefore, should be

    A)  \[98.96{}^\circ C\]          

    B)  \[100.52{}^\circ C\]

    C)  \[101.04{}^\circ C\]       

    D)  \[107.01{}^\circ C\]

    Correct Answer: C

    Solution :

                    \[\Delta {{T}_{b}}=in{{k}_{b}}=0.52\times 1\times 2=1.04\] \[\therefore \] \[{{T}_{b}}=T+\Delta {{T}_{b}}=100+1.04=101.4{}^\circ C\]


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