A) 5, 1, 6
B) 1, 5, 6
C) 6, 1, 5
D) 5, 6, 1
Correct Answer: A
Solution :
\[{{I}^{-}}+\overset{+5}{\mathop{{{(I{{O}_{3}})}^{-}}}}\,+{{H}^{-}}\to \overset{0}{\mathop{{{I}_{2}}}}\,+{{H}_{2}}O\] \[2{{I}^{-}}\xrightarrow{{}}{{I}_{2}}+2{{e}^{-}}\] ?(i) x 5 \[10{{e}^{-}}+\overset{+5}{\mathop{2{{(I{{O}_{3}})}^{-1}}}}\,\xrightarrow{{}}\overset{0}{\mathop{{{I}_{2}}}}\,\] ?(ii) On adding Eqs. (i) and (ii), we get \[10{{I}^{-}}+2IO_{3}^{-}\xrightarrow{{}}6{{I}_{2}}\] To balance O atom, add \[6{{H}_{2}}O\]molecules/on RHS and \[12{{H}^{+}}\]on LHS, then \[10{{I}^{-}}+2IO_{3}^{-}+12{{H}^{+}}\xrightarrow{{}}6{{I}_{2}}+6{{H}_{2}}O\] or \[5{{I}^{-}}+IO_{3}^{-}+6{{H}^{+}}\xrightarrow{{}}3{{I}_{2}}+3{{H}_{2}}O\]You need to login to perform this action.
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