A) \[98.96{}^\circ C\]
B) \[100.52{}^\circ C\]
C) \[101.04{}^\circ C\]
D) \[107.01{}^\circ C\]
Correct Answer: C
Solution :
\[\Delta {{T}_{b}}=in{{k}_{b}}=0.52\times 1\times 2=1.04\] \[\therefore \] \[{{T}_{b}}=T+\Delta {{T}_{b}}=100+1.04=101.4{}^\circ C\]You need to login to perform this action.
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