A) 57 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[57\times {{10}^{-3}}\]\[\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) 217100 \[\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[11.61\times {{10}^{-33}}\]\[\overset{\text{o}}{\mathop{\text{A}}}\,\] (Plancks constant \[h=6.6\times {{10}^{-34}}\]Js)
Correct Answer: C
Solution :
The energy of photon \[=\frac{hc}{\lambda },\]which should be equal to 57 MeV \[=57\times {{10}^{-3}}\times 1.6\times {{10}^{-19}}J\] Therefore, \[\lambda =\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{57\times {{10}^{-3}}\times 1.6\times {{10}^{-19}}}\] \[=0.2171\times {{10}^{-4}}m\] \[=217100\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
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