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CMC Medical CMC-Medical Ludhiana Solved Paper-2011

  • question_answer
    \[C{{H}_{3}}COOH\xrightarrow{LiAl{{H}_{4}}}X\xrightarrow[300{}^\circ C]{Cu}Y\xrightarrow[NaOH]{Dilute}Z\]In the above reaction Z is

    A)  butanol              

    B)  aldol

    C)  ketol                                    

    D)  acetal

    Correct Answer: B

    Solution :

    \[\underset{acetic\,acid}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow{LiAl{{H}_{4}}}\underset{(X)}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow[300{}^\circ C]{Cu}\] \[C{{H}_{3}}CHO\xrightarrow{\begin{smallmatrix}  Dil.\,NaOH \\  (aldol\,\,condensation) \end{smallmatrix}}\]             \[C{{H}_{3}}-\underset{\begin{smallmatrix}  OH \\  (Z)\,aldol \end{smallmatrix}}{\mathop{\underset{\mathbf{|}}{\mathop{CH}}\,}}\,-C{{H}_{2}}CHO\]


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