A) 2
B) \[2+\sqrt{2}\]
C) \[2-\sqrt{2}\]
D) \[2\pm \sqrt{2}\]
Correct Answer: B
Solution :
\[h=\frac{1}{2}g{{t}^{2}}\] \[\frac{h}{2}=\frac{1}{2}g{{(t-1)}^{2}}\] Solving Eqs. (i) and (ii), we get \[t=2\pm \sqrt{2}\,g\] \[t=(2+\sqrt{2})\,s\]You need to login to perform this action.
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