A) 1 : 1
B) 2 : 3
C) 3 : 4
D) 1 : \[\sqrt{2}\]
Correct Answer: B
Solution :
\[{{a}_{1}}=\frac{g\sin 30{}^\circ }{1+\frac{1}{2}}=\frac{2}{3}g\,\sin \theta \] ?(i) \[{{a}_{2}}=g\,\sin \theta \] ?(ii) From Eqs. (i) and (ii), we get \[\Rightarrow \] \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{2}{3}\]You need to login to perform this action.
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